truck
krysdizzle_2006 asked:


You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass(3,000 kg each) were involved in a rear-end accident at a stop sign. here is what you know:
Truck 1 approched the intersection from the top of a 22-meter hill.
Truck 2 was on a flat stretch of road directly in front of truck 1.
At the bottom of the hill, before braking for the stop sign, Truck 1 was going 20 m/s and truck 2 was going 35 m/s.
From the skid marks on the road you can see that truck 1 applied force on its brakes for 2 seconds, 80 meters before the stop sign.
There were no skid marks left by truck 2. The collision occured at the stop sign, where truck 2 had stopped.
After the collision, both trucks were moving together in the same direction at 10 m/s, before slowly rolling to a stop.
You must now push truck 2 using 1,000 N of force, 8 meters off the side of the road so no one else gets hurt.

DANTE
Share It All and Enjoy: These icons link to social bookmarking sites where readers can share and discover new web pages.
  • Digg
  • del.icio.us
  • StumbleUpon
  • Reddit
  • Webnews
  • MisterWong
  • Y!GG
  • Ask
  • Blogosphere News
  • Bumpzee
  • connotea
  • De.lirio.us
  • Faves
  • Folkd
  • Furl
  • Linkarchiv
  • Linkarena
  • LinkedIn
  • MyShare
  • MySpace
  • Netscape
  • Print
  • Propeller
  • Scoopeo
  • Segnalo
  • Slashdot
  • Social-Bookmarking.dk
  • Socialdust
  • SphereIt
  • Sphinn
  • Squidoo
  • Technorati
  • TwitThis
  • VoteForIt
  • YahooBuzz
  • YahooMyWeb

Comments

emsviper on 28 April, 2008 at 4:10 pm #

OK — so you want to know the energy? Since you’re going from the top of a hill to its bottom, you know that all of your gravitational potential energy is going to be changed into kinetic energy. Since the truck applied its brakes you know that some of that energy was lost so instead of Ug = KE = mgh = 0.5mv^2 you get Ug = KE - f


Post a Comment
Name:
Email:
Website:
Comments: